我试图计算值计数，如果通用=== 在多个子数组下为真，但我没有成功如何使用java脚本减少函数来获得总计4总和应为 4，因为只有 4 个对象具有共同点 === trueconst obj = { "A": [ [ { "count": "1.00", "common": false },{ "count": "1.00", "common": true } ], [ { "count": "1.00", "common": false }, { "count": "1.00", "common": true } ] ], "B": [ [ { "count": "1.00", "common": false },{ "count": "1.00", "common": true } ], [ { "count": "1.00", "common": false }, { "count": "1.00", "common": true } ] ]};let total = Object.values(obj).reduce((acc, value) => acc + value.reduce((a,b) => a+b.reduce((c,d) => c + (d.common) ? parseInt(d.count) : 0,0),0), 0);
3 回答
慕容708150
TA贡献1831条经验 获得超4个赞
您将嵌套数组作为对象的值，您需要两个内部循环来获取所需的求和属性
const
obj = { A: [[{ count: "1.00", common: false }, { count: "1.00", common: true }], [{ count: "1.00", common: false }, { count: "1.00", common: true }]], B: [[{ count: "1.00", common: false }, { count: "1.00", common: true }], [{ count: "1.00", common: false }, { count: "1.00", common: true }]] },
total = Object
.values(obj)
.reduce((r, outer) => {
outer.forEach(inner =>
inner.forEach(({ common, count }) => r += common ? +count : 0)
);
return r;
}, 0);
console.log(total); // 4
有只小跳蛙
TA贡献1824条经验 获得超8个赞
另一种方法是使用以下方法拼合数组，然后应用：concatreduce
const obj = {
"A": [
[{"count": "1.00", "common": false}, {"count": "1.00", "common": true}],
[{"count": "1.00", "common": false}, {"count": "1.00", "common": true}]
],
"B": [
[{"count": "1.00", "common": false}, {"count": "1.00", "common": true}],
[{"count": "1.00", "common": false}, {"count": "1.00", "common": true}]
]
};
const sum = [].concat(...([].concat(...Object.values(obj))))
.reduce(( acc, cur ) => acc + (cur.common ? +cur.count : 0), 0)
console.log(`Total count = ${sum}`);
隔江千里
TA贡献1906条经验 获得超10个赞
这是另一种方式
const obj = {
"A": [
[
{
"count": "1.00",
"common": false
},{
"count": "1.00",
"common": true
}
],
[
{
"count": "1.00",
"common": false
},
{
"count": "1.00",
"common": true
}
]
],
"B": [
[
{
"count": "1.00",
"common": false
},{
"count": "1.00",
"common": true
}
],
[
{
"count": "1.00",
"common": false
},
{
"count": "1.00",
"common": true
}
]
]
};
let total = 0;
Object.values(obj).forEach(c => c.forEach(arr => total += arr.filter(o => o.common).length));
console.log("Total: " + total);
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