在 Android 的测试方法中调用的模拟方法如何？

Question

我为我的 android 应用程序编写测试，我需要从我的类中模拟一个方法，该方法在我测试的方法中调用。这是我的课：public class MyFirebaseMessagingService extends FirebaseMessagingService {..... @Overridepublic void onMessageReceived(RemoteMessage remoteMessage) {            if (!isAppOnForeground(this)) {                DoSomeThing();            }        }    }public boolean isAppOnForeground(Context context) {       return isAppOnForeground;    }}我想在返回真假onMessageReceived时测试方法。isAppOnForeground我试试@Testpublic void onMessageReceived() {MyFirebaseMessagingService mockMyFirebaseMessagingService = org.mockito.Mockito.mock(MyFirebaseMessagingService.class);when(mockMyFirebaseMessagingService.isAppOnForeground(any(Context.class))).thenReturn(false);mockMyFirebaseMessagingService.onMessageReceived(remoteMessage);...}但是当我运行这个测试时，我没有看到方法调用onMessageReceived（断点不起作用）。我怎样才能嘲笑isAppOnForeground和打电话onMessageReceived？

Answer 1

你看不到onMessageReceived()方法正在运行，因为它没有。

MyFirebaseMessagingService mockMyFirebaseMessagingService = org.mockito.Mockito.mock(MyFirebaseMessagingService.class);

您正在创建一个模拟，一个空模拟，它对原始类的实现一无所知。

你想spy()改用。尝试这个：

MyFirebaseMessagingService myFirebaseMessagingService = new MyFirebaseMessagingService();

MyFirebaseMessagingService mockMyFirebaseMessagingService = org.mockito.Mockito.spy(myFirebaseMessagingService);

doReturn(false).when(mockMyFirebaseMessagingService).isAppOnForeground(any(Context.class));

mockMyFirebaseMessagingService.onMessageReceived(remoteMessage);