当时间是时间数组中的时间时，从单词数组中返回一个单词。

Question

我正在使用 React 为音频或视频文件构建转录服务。后端完成了，我得到了这两个数组：我有一个时间数组，以秒为单位：const timing = [0, 0.2, 0.8, 0.9, 1.3, 2]我还有一系列单词：const words = ["hello", "world", "I", "am", "John", "Smith"]我只想在时机合适时突出显示一个单词。除了无限的“if”语句之外，还有其他方法吗？if(time = timing[0]) {return words[0]}if(time = timing[1]) {return words[1]}...if(time = timing[n]) {return words[n]}（*时间等于视频/音频播放器）谢谢！

Answer 1

如果你使用 dict 和 setInterval 会更容易

const words = {

    0: "hello",

  200: "world",

  800: "I",

  900: "am",

  1300: "John",

  2000: "Smith"

}

function speak(timing) {

    if(timing in words) {

    console.log(words[timing])

  }

}

current_timestamp = 0

function timer() {

    speak(current_timestamp)

  current_timestamp += 100

}

setInterval(timer, 100);

Answer 2

const timing = [0, 0.2, 0.8, 0.9, 1.3, 2];

const words = ['hello', 'world', 'I', 'am', 'John', 'Smith'];

function getWord(timing, words, time) {

    return words[timing.indexOf(time)];

}

console.log(getWord(timing, words, 0.9));

Answer 3

我认为你可以这样做：

const timing = [0, 0.2, 0.8, 0.9, 1.3, 2]

const words = ["hello", "world", "I", "am", "John", "Smith"];

var hashTable = {}

timing.forEach((i, index)=>{

  hashTable[i] = words[index];

});

console.log(hashTable)

   console.log(hashTable[timing[3]])