这可以用SQL来完成吗?我需要根据 $query 是否为false WHERE (u.id_user = ".$userId." OR fu.id_user = ".$userId." OR ff.id_user = ".$userId.")"ELSE来进行 SQL 选择"$query";这是我必须满足两个条件的起点: $validatedSearchData = array( "q"=>strip_tags($_GET["q"]) ); $query= " AND a.tags LIKE ".lib::$db->qstr("%".$validatedSearchData["q"]."%"); $feed = lib::$db->GetAll("SELECT SQL_CALC_FOUND_ROWS a.*, u.name, fu.id_user AS fu_user_id, ff.id_followed_user AS ff_user_id FROM feed AS a LEFT JOIN userfollow AS fu ON a.id_author = fu.id_user LEFT JOIN userfollow AS ff ON a.id_author = ff.id_followed_user INNER JOIN user_profiles AS u ON a.id_author = u.id_user WHERE (u.id_user = ".$userId." OR fu.id_user = ".$userId." OR ff.id_user = ".$userId.")" . $query. " GROUP BY a.id_article ");
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吃鸡游戏
TA贡献1829条经验 获得超7个赞
更改此行
$query= " OR a.tags LIKE ".lib::$db->qstr("%".$validatedSearchData["q"]."%");
用 OR 代替 AND
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