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Web api 响应中的额外花括号使响应无法转换为模型

Web api 响应中的额外花括号使响应无法转换为模型

C#
桃花长相依 2022-10-15 14:13:35
我正在尝试阅读 Yelp API。下面是我的代码。public async Task<HttpContent> InvokeApi(string path, HttpAction action, HttpContent content = null, TimeSpan? overrideTimeout = null, string externalServer = null)    {        var sUrl = externalServer == null ? ServerUrl : externalServer;        using (var client = new HttpClient())        {            client.BaseAddress = new Uri(sUrl);            if (overrideTimeout.HasValue)            {                client.Timeout = overrideTimeout.Value;            }            //this.Log("Connecting to {0} Api at {1}".Fmt(WebPortalServer, ServerUrl));            client.DefaultRequestHeaders.Authorization = new AuthenticationHeaderValue("bearer", AccessToken);            client.DefaultRequestHeaders.Accept.Clear();            client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));            HttpResponseMessage response;            switch (action)            {                case HttpAction.Get:                    response = await client.GetAsync(path);                    break;                case HttpAction.Post:                    response = await client.PostAsync(path, content);                    break;                case HttpAction.Put:                    response = await client.PutAsync(path, content);                    break;                case HttpAction.Delete:                    response = await client.DeleteAsync(path);                    break;                default:                    throw new ArgumentOutOfRangeException("action", action, null);            }            return response.IsSuccessStatusCode ? response.Content : null;        }    }我从这个 api 得到的响应嵌入在花括号中,因此它不允许我将响应转换为 Yelp 模型。响应的开头和结尾有一对额外的花括号。如何以正确的 Json 格式获取响应。
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3 回答

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慕的地8271018

TA贡献1796条经验 获得超4个赞

的呼唤


all.ReadAsAsync<Object>().Result;

JObject返回一个不能通过简单转换转换为的实例Yelp。而是ReadAsAsync像这样调用


var business = await all.ReadAsAsync<Common.Models.Yelp.Yelp>();

return business;

如果你仍然想调用它,object你可以这样做


var business = await all.ReadAsAsync<object>();

return ((JObject)business).ToObject<Yelp>();

笔记


响应 json 不包含额外的花括号。它只是JObject将它们添加到调试视图中。通过检查将响应读取为字符串的结果很容易检查这一点all.ReadAsStringAsync().Result。


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反对 回复 2022-10-15
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哔哔one

TA贡献1854条经验 获得超8个赞

使用 JSON.NET 的Deserialize 方法使用泛型类型重载将字符串反序列化为所需的 POCO。

public async Task<HttpContent> InvokeApi(string path, HttpAction action, HttpContent content = null, TimeSpan? overrideTimeout = null, string externalServer = null)

{


    var sUrl = externalServer == null ? ServerUrl : externalServer;


    using (var client = new HttpClient())

    {

        client.BaseAddress = new Uri(sUrl);

        if (overrideTimeout.HasValue)

        {

            client.Timeout = overrideTimeout.Value;

        }

        //this.Log("Connecting to {0} Api at {1}".Fmt(WebPortalServer, ServerUrl));

        client.DefaultRequestHeaders.Authorization = new AuthenticationHeaderValue("bearer", AccessToken);

        client.DefaultRequestHeaders.Accept.Clear();

        client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));


        HttpResponseMessage response;


        switch (action)

        {

            case HttpAction.Get:

                response = await client.GetAsync(path);

                break;

            case HttpAction.Post:

                response = await client.PostAsync(path, content);

                break;

            case HttpAction.Put:

                response = await client.PutAsync(path, content);

                break;

            case HttpAction.Delete:

                response = await client.DeleteAsync(path);

                break;

            default:

                throw new ArgumentOutOfRangeException("action", action, null);

        }


        return response.IsSuccessStatusCode ? response.Content : null;

    }

}


public async Task<Common.Models.Yelp.Yelp> GetAllBusiness(decimal latitude, decimal longitude)

{

    HttpContent all = await _webPortalApiClient.InvokeApi($"businesses/search?limit=10&latitude={latitude}&longitude={longitude}", HttpAction.Get, null, null, "https://api.yelp.com/v3/");

    if (all == null)

    {

        return null;

    }



    string responseBody = await all.ReadAsStringAsync();


    // Deserialize from serialized string into your POCO

    var business = JsonConvert.DeserializeObject<Common.Models.Yelp.Yelp>(responseBody);

    return business;

}




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反对 回复 2022-10-15
?
幕布斯7119047

TA贡献1794条经验 获得超8个赞

var business = all.Result;  

 var resultString = business.ReadAsStringAsync();  

 return JsonConvert.DeserializeObject<Common.Models.Yelp.Yelp>(resultString);


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反对 回复 2022-10-15
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