如果特定值相同，我想要一个合并子数组的函数

Question

我有如下二维数组：[ ['Procare Fitted 医院床底床单，象牙色'，'DT4098'，'Demo'，null，12300，2]，['Essential Medical Supply Deluxe Complete Hospital Bed Set'，'ERT665'，'Demo'，null， 11790, 2]，['博士。Morepen St 04 声学听诊器', 'DT4098', 'Demo', null, 21237, 2], ['CosmoCare KLife 5 Para Patient Monitor', 'YTT690', 'Demo', null, 11000, 2], ['CosmoCare KLife 5 Para Patient Monitor', 'YTT690', 'Demo', null, 11000, 2], ['CosmoCare KLife 5 Para Patient Monitor', 'YTT690', 'Demo', null, 11000, 2], ['CosmoCare KLife 5 Para Patient Monitor', 'YTT690', 'Demo', null, 11000, 2], ['Dr. Morepen St 04 声学听诊器', 'DT4098', 'Demo', null, 21237, 2],我只想根据子数组的第一个索引从多维数组中删除重复值。如果第一个索引值相同，则删除重复的子数组。[ ['Procare Fitted 医院床底床单，象牙色'，'DT4098'，'Demo'，null，12300，6]，['Essential Medical Supply Deluxe Complete Hospital Bed Set'，'ERT665'，'Demo'，null， 11790, 6], ['CosmoCare KLife 5 Para Patient Monitor', 'YTT690', 'Demo', null, 11000, 4]];

Answer 1

我希望这对你有帮助。

var myArray = [ [ 'Procare Fitted Hospital Bed Bottom Sheet, Ivory',

    'DT4098',

    'Demo',

    null,

    12300,

    2],

  [ 'Essential Medical Supply Deluxe Complete Hospital Bed Set',

    'ERT665',

    'Demo',

    null,

    11790,

    2],

  [ 'Dr. Morepen St 04 Acoustic Stethoscope',

    'DT4098',

    'Demo',

    null,

    21237,

    2],

  [ 'CosmoCare KLife 5 Para Patient Monitor',

    'YTT690',

    'Demo',

    null,

    11000,

    2],

  [ 'CosmoCare KLife 5 Para Patient Monitor',

    'YTT690',

    'Demo',

    null,

    11000,

    2],

  [ 'CosmoCare KLife 5 Para Patient Monitor',

    'YTT690',

    'Demo',

    null,

    11000,

    2],

  [ 'CosmoCare KLife 5 Para Patient Monitor',

    'YTT690',

    'Demo',

    null,

    11000,

    2],

  [ 'Dr. Morepen St 04 Acoustic Stethoscope',

    'DT4098',

    'Demo',

    null,

    21237,

    2],

  [ 'Essential Medical Supply Deluxe Complete Hospital Bed Set',

    'ERT665',

    'Demo',

    null,

    11790,

    2],

  [ 'Essential Medical Supply Deluxe Complete Hospital Bed Set',

    'ERT665',

    'Demo',

    null,

    11790,

    2] ];

   let duplicates = [];

    let output = myArray.reduce((t, i) => {

      if(duplicates.includes(i[1])) {

        let myArray = t.filter((item) => item[1] == i[1])[0];

        myArray[5] += i[5];

        t = t.filter((item) => item[1] != i[1]);

        i = myArray;

      } else {

        duplicates.push(i[1]);

      }

      t.push(i);      

      return t;

    }, []);

    

    console.log(output);