将条件实现到数组中

Question

我正在尝试在我的程序中实现另一个条件，但似乎无法弄清楚。这是代码：print ("Welcome to the winning card program.")year_one=[]year_one.append(eval(input("Enter the salary individual 1 got in year 1:  ")))year_one.append(eval(input("Enter the salary individual 2 got in year 1:  "))) if year_one[0]==year_one[1]:   print("Error. The amount are the same, please reenter information.")year_two=[]year_two.append(eval(input("Enter the salary individual 1 got in year 2:  ")))year_two.append(eval(input("Enter the salary individual 2 got in year 2:  "))) if year_two[0]==year_two[1]:   print("Error. The amount are the same, please reenter information.")year_three=[]year_three.append(eval(input("Enter the salary individual 1 got in year 3:  ")))year_three.append(eval(input("Enter the salary individual 2 got in year 3:  ")))  if year_three[0]==year_three[1]:   print("Error. The amount are the same, please reenter information.")year_four=[]year_four.append(eval(input("Enter the salary individual 1 got in year 4:  ")))year_four.append(eval(input("Enter the salary individual 2 got in year 4:  "))) if year_four[0]==year_four[1]:  print("Error. The amount are the same, please reenter information.")year_five=[]year_five.append(eval(input("Enter the salary individual 1 got in year 4:  ")))year_five.append(eval(input("Enter the salary individual 2 got in year 4:  "))) if year_five[0]==year_five[1]:  print("Error. The amount are the same, please reenter information.")individual1_total=year_one[0]+year_two[0]+year_three[0]+year_four[0]+year_five[0]individual2_total=year_one[1]+year_two[1]+year_three[1]+year_four[1]+year_five[1] if (individual1_total>individual2_total):  print("Individual one has the highest salary.") elif (individual2_total>individual1_total):  print("Individual two has the highest salary.")如果两个人在某一年的薪水完全相同，您应该打印一个错误并让用户再次输入该年的薪水。（条件是工资不应该完全相同）。我期待大家的反馈。先感谢您。

Answer 1

好的，所以在这里建立 Surge10 可以更完整地替换您的代码。我将所有部分分解为函数，并制作了一个字典作为我的内存数据库。

total_years = 5

years = {}

def dict_key(year, userId):

    return '{}:{}'.format(year, userId)

def get_user_data(year, userId):

    key = dict_key(year, userId)

    years[key] = float(input("Enter the salary individual {} got in year {}:".format(userId, year)))

def get_year_salaray(year, userId):

    key = dict_key(year, userId)

    return years[key]

def any_salaries_match(year, userIds):

    for userLeft in userIds:

        salary_left = get_year_salaray(year, userLeft)

        for userRight in userIds:

            if userLeft != userRight:

                salary_right = get_year_salaray(year, userRight)

                if salary_left == salary_right:

                    return True

def get_user_totals(userId):

    total = 0

    for key, value in years.items():

        if ':{}'.format(userId) in key:

            total += value

    return total

for x in range(total_years):

    year = x + 1

    data_invalid = True

    while data_invalid:

        userOne = 1

        userTwo = 2

        get_user_data(year, userOne)

        get_user_data(year, userTwo)

        if any_salaries_match(year, [userOne, userTwo]):

            print("Error. The amount are the same, please reenter information.")

        else:

            data_invalid = False

userOneTotal = get_user_totals(1)

userTwoTotal = get_user_totals(2)

if (userOneTotal>userTwoTotal):

  print("Individual one has the highest salary.")

elif (userTwoTotal>userOneTotal):

  print("Individual two has the highest salary.")

Answer 2

因为我们检查了五个不同的年份，所以我对这五年使用了一个循环。稍后我们可以将它恢复到各个年份。

print ("Welcome to the winning card program.")

years=[]

for x in range(5):

    # range starts at zero so add one all the time

    # to start it at one

    y = str(x + 1)

    errors = True

    while errors:

        salary_one = input("Enter the salary individual 1 got in year " + y + ":  ")

        salary_two = input("Enter the salary individual 2 got in year " + y + ":  ")

        if salary_one == salary_two:

            print("Error. The amount are the same, please reenter information.")

            errors = True

        else:

            years.append([salary_one, salary_two])

            errors = False

year_one = years[0]

year_two = years[1]

...

print(year_one)

print(year_two)

...