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删除常见的观察

删除常见的观察

翻阅古今 2022-11-01 14:01:38
我有 2 个数据框Map3 = pd.DataFrame({"partner_country": ["France","France","France","France","France","France",                     "Spain","Spain","Spain","Spain","Spain","Spain"                    ],"my_network": ["Ireland","Austria",None,"Sweden","Italy",None , #France               "Ireland","Austria","Denmark","Sweden",None,"United Kingdom" #Spain               ]})#NetherlandsMap4 = pd.DataFrame({"partner_country": ["France","France","France","France","France","France",                     "Spain","Spain","Spain","Spain","Spain","Spain"                    ],"my_network": [None,None,None,None,"Italy",None , #France               None,"Austria",None,"Sweden",None,"United Kingdom" #Spain               ]})#Netherlands我想从 Map3 数据框中删除 Map3 和 Map4 中常见的所有观察结果。尝试了以下代码:Map4[~(Map4['partner_country'].isin(Map3['partner_country'])Map4['my_network'].isin(Map3['my_network']]
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宝慕林4294392

TA贡献2021条经验 获得超8个赞

由于您只有 2 列,因此一个简单的解决方案可能是:

common = (Map3.partner_country + Map3.my_network).isin(Map4.partner_country + Map4.my_network)Map3 = Map3.loc[~common]


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反对 回复 2022-11-01
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