如何将单词添加到小列表值

Question

list=["Book","Glass","Book,"Watch","Doll,"Book"]def a_list(list)输出：The List is:BookGlassBookWatchDollBook检查后的清单：BookGlass uniqueBookWatch uniqueDoll uniqueBook

Answer 1

您可以简单地使用collections.Counter来检测计数不超过 1 的唯一项目。

from collections import Counter

lst=["Book","Glass","Book","Watch","Doll","Book"]

def a_list(items):

    # Count the words

    counts = Counter(items)

    for item in items:

        # Found a non-unique item, don't add "unique" to it

        if counts[item] > 1:

            print(item)

        # Found a unique item, add "unique" to it

        else:

            print(item, "unique")

a_list(lst)

输出：

Book

Glass unique

Book

Watch unique

Doll unique

Book

我们还可以将这些项目附加到一个新列表并返回它：

def a_list(items):

    counts = Counter(items)

    result = []

    for item in items:

        if counts[item] > 1:

            result.append(item)

        else:

            result.append(f"{item} unique")

    return result

print(a_list(lst))

或使用列表理解：

def a_list(items):

    counts = Counter(items)

    return [item if counts[item] > 1 else f"{item} unique" for item in items]

print(a_list(lst))

输出：

['Book', 'Glass unique', 'Book', 'Watch unique', 'Doll unique', 'Book']

Answer 2

一个简单的方法是：

ll=["Book","Glass","Book","Watch","Doll","Book"]

def a_list(l):

    for elem in l:

        if l.count(elem) > 1:

            print(elem)

        else:

            print(elem, "unique")

a_list(ll)

这将提供所需的输出。

如果你想改变列表并返回它，应该使用相同的逻辑，但你应该改变元素本身，而不是打印，如下所示：

ll=["Book","Glass","Book","Watch","Doll","Book"]

def a_list(l):

    for i, elem in enumerate(l):

        if l.count(elem) > 1:

            l[i] = "{:} unique".format(elem)

    return l

lll = a_list(ll)

print(lll)