如何在包含具有数组值的子对象的对象中搜索值

Question

我有 json 对象，我想在其中搜索一个键，如果键匹配，则返回该对象键作为结果。考虑下面的例子obj = {    "India": {        "Karnataka": ["Bangalore", "Mysore"],        "Maharashtra": ["Mumbai", "Pune"]    },    "USA": {        "Texas": ["Dallas", "Houston"],        "IL": ["Chicago", "Aurora", "Pune"]    }}input: Puneoutput: ['Maharashtra','IL']

Answer 1

你可以试试这个-

const obj = {

  "India" : {

    "Karnataka" : ["Bangalore", "Mysore"],

    "Maharashtra" : ["Mumbai", "Pune"]

  },

  "USA" : {

    "Texas" : ["Dallas", "Houston"],

    "IL" : ["Chicago", "Aurora", "Pune"]

  }

};

const search = (obj, keyword) => {

  return Object.values(obj).reduce((acc, curr) => {

      Object.entries(curr).forEach(([key, value]) => {

        if (value.indexOf(keyword) > -1) {

          acc.push(key);

        }

      });

    return acc;

  }, []);

}

console.log(search(obj, 'Pune'));

这将搜索keyword数组中是否存在。如果然后将钥匙推入reduce蓄电池。

Answer 2

假设您的数据将始终采用 country:state:city 的形式，您可以执行以下操作。获取键的数组，如下所示：

keys = Object.keys(obj);

然后遍历每个键：

function classify(input){

res = [];

Object.keys(obj).forEach((key)=>{

   states = obj[key];

   Object.keys(states).forEach((stateKey)=>{

      if(states[stateKey].includes(input)){

         res.push([stateKey,key]);

      }

   })

})

return(res);}

这也将返回一个包含国家/地区的数组：

input: Pune

output: [['Maharashtra','India'],['IL','USA']]

Answer 3

const input = "Pune"

const result = []

for (v1 in obj) {

  for (v2 in obj[v1]) {

    for (let i = 0; i < obj[v1][v2].length; i++) {

      if (obj[v1][v2][i] === input) {

        result.push([v2][0])

      }

    }

  }

}

Answer 4

function isObject (variable) { 

return variable !== undefined && variable !== null && variable.constructor === Object

}

function find(obj,value,keyPath = []){

   let values = Object.values(obj) 

   let keys = Object.keys(obj)

  

   for(let i in values){

      if(isObject (values[i])) {

         find(values[i],value,keyPath )

          

      }else if(Array.isArray(values[i])){

         let foundValue = values[i].find(e=>value==e)

         if(foundValue ){

            keyPath.push(keys[i]) 

         }

      }

   }

   return keyPath 

}

obj = { "India": { "Karnataka": ["Bangalore", "Mysore"], "Maharashtra": ["Mumbai", "Pune"] }, "USA": { "Texas": ["Dallas", "Houston"], "IL": ["Chicago", "Aurora", "Pune"] } }

console.log(find(obj,"Dallas"))

这应该这样做。它应该能够做任何深度。