检查是否所有对象键都作为对象数组中的值存在

Question

假设我有这两个实体const obj1 = {key1: "", key2: "", key3: ""};const array2 = [  {    name: "key1",  }]如何检查是否array2有一个对象具有每个字段的名称obj1？基本上我想以数组 2 变成这样结束：const array2 = [  {    name: "key1",  },{    name: "key2",  },{    name: "key3",  }]

Answer 1

是这样的吗？

const obj1 = {

    key1: "",

    key2: "",

    key3: ""

};

const array2 = [{

    name: "key1",

}, {

    name: "key2",

}];

const obj1Keys = Object.keys(obj1);

const array2KeyNames = array2.reduce((array2KeyNames, obj) => {

    array2KeyNames.push(obj.name);

    return array2KeyNames;

}, []);

for (let i = 0; i < obj1Keys.length; i++) {

    if (!array2KeyNames.includes(obj1Keys[i])) {

        console.log(obj1Keys[i], ' is not in the array2');

        break;

    }

}