3 回答
TA贡献1794条经验 获得超7个赞
`所以,根据你的问题,我了解到你想为每个元素提供 id 和获取的数组中的值。
所以对于第一个<li>元素,id 将是category 1。如果这是您要的,解决方案是获取所需的元素
<div id="parent">
<ul>
<li role="presentation" class="active categories"><a href="#all" aria-controls="all" role="tab" data-toggle="tab">ALL</a></li>
<li role="presentation" class="categories"><a href="#chicken" aria-controls="chicken" role="tab" data-toggle="tab">CHICKEN</a></li>
<li role="presentation" class="categories"><a href="#fish" aria-controls="fish" role="tab" data-toggle="tab">FISH</a></li>
<li role="presentation" class="categories"><a href="#turkey" aria-controls="turkey" role="tab" data-toggle="tab">TURKEY</a></li>
<li role="presentation" class="categories"><a href="#miscellenous" aria-controls="miscellenous" role="tab" data-toggle="tab">MISCELLANOUS</a></li>
<li role="presentation" class="categories"><a href="#frozen" aria-controls="last" role="tab" data-toggle="tab">LAST</a></li>
</ul>
</div>
let fetchedArray = ['cat1','cat2','cat3','cat4','cat5','cat6'];
$('li').each((i,el) => {
$(el).attr('id',fetchedArray[i]);
})
TA贡献1843条经验 获得超7个赞
`所以,根据你的问题,我了解到你想为每个元素提供 id 和获取的数组中的值。
所以对于第一个<li>元素,id 将是category 1。如果这是您要的,解决方案是获取所需的元素
<div id="parent">
<ul>
<li role="presentation" class="active categories"><a href="#all" aria-controls="all" role="tab" data-toggle="tab">ALL</a></li>
<li role="presentation" class="categories"><a href="#chicken" aria-controls="chicken" role="tab" data-toggle="tab">CHICKEN</a></li>
<li role="presentation" class="categories"><a href="#fish" aria-controls="fish" role="tab" data-toggle="tab">FISH</a></li>
<li role="presentation" class="categories"><a href="#turkey" aria-controls="turkey" role="tab" data-toggle="tab">TURKEY</a></li>
<li role="presentation" class="categories"><a href="#miscellenous" aria-controls="miscellenous" role="tab" data-toggle="tab">MISCELLANOUS</a></li>
<li role="presentation" class="categories"><a href="#frozen" aria-controls="last" role="tab" data-toggle="tab">LAST</a></li>
</ul>
</div>
let fetchedArray = ['cat1','cat2','cat3','cat4','cat5','cat6'];
$('li').each((i,el) => {
$(el).attr('id',fetchedArray[i]);
})
TA贡献1824条经验 获得超6个赞
如果要更改 id,可以使用 for 循环遍历元素并更改它们。
const categories = ["category 1", "category 2", "category 3", "category 4", "category 5", "category 6"];
for (var i = 0; i < document.getElementsByTagName("li").length; i++) {
let el = document.getElementsByTagName("li")[i];
el.id = categories[i];
console.log(el);
}
<li role="presentation" class="active categories"><a href="#all" aria-controls="all" role="tab" data-toggle="tab">ALL</a></li>
<li role="presentation" class="categories"><a href="#chicken" aria-controls="chicken" role="tab" data-toggle="tab">CHICKEN</a></li>
<li role="presentation" class="categories"><a href="#fish" aria-controls="fish" role="tab" data-toggle="tab">FISH</a></li>
<li role="presentation" class="categories"><a href="#turkey" aria-controls="turkey" role="tab" data-toggle="tab">TURKEY</a></li>
<li role="presentation" class="categories"><a href="#miscellenous" aria-controls="miscellenous" role="tab" data-toggle="tab">MISCELLANOUS</a></li>
<!--
<li role="presentation" class="categories">
<a href="#frozen" aria-
-->
上面的代码遍历了lis
并将 ids 附加到 中的元素categories
。然后它将元素打印到控制台,这样您就可以看到它们的 id 是如何设置的。
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