我这样赋值,输出的时候会报错....为什么呢

Question

结构体是这样的struct bf{unsigned char header;unsigned char length;unsigned char address;unsigned char command;unsigned char x[3];unsigned char y[3];unsigned char z[3];unsigned char checksum;  };将下面这串字符串赋值取出一部分 赋值给上面的结构体unsigned char a[] = {0x68,0x0D,0x00,0x04,0x20,0x10,0x10,0x58,0x00,0x04,0x05,0x00,0x00,0x32,0x68,0x0D,0x00,0x84,0x20,0x10,0x10,0x58,0x00,0x04,0x05,0x00,0x00,0x32,0x68,0x0D};struct bf *buff;buff = (struct bf *)malloc(sizeof(struct bf));memcpy(buff,getbuf,14);

Answer 1

结构体赋值要求是内存对齐的。请问您这个字符串对齐了么？

Answer 2

常用的方法是：直接强制类型转换。
前提是：1、接收的数据是先低后高的，2、结构体按1字节对齐

#program pack(push) 
#program pack(1)
结构体定义。。。
#program pack(pop)

struct bf * buff = NULL;
buff = (bf*)&a[0];//呵，当然a也可以