在对象数组中搜索特定值并返回多个结果

Question

我需要在多个数组中找到具有特定值的所有对象，返回所有匹配对象的图像的另一个值。我会尝试用一个例子让它更清楚一点。我正在搜索每个target具有值的值find-me并获取source返回值。有些数组有匹配的对象，有些可能没有。结果数组应具有唯一值。const deps = {  "something": [    {      "type": "static",      "source": "foo",      "target": "bar"    },    {      "type": "static",      "source": "return-me",      "target": "find-me"    }  ],  "anything": [    {      "type": "static",      "source": "and-me",      "target": "find-me"    }  ],  "no-match": [    {      "type": "static",      "source": "foo",      "target": "bar"    }  ]}所以对于这个例子，结果应该是['return-me', 'and-me']我试过这个：const search = 'find-me'const sources = Object  .values(deps)  .flat()  .find(el => el.target === search)  .map(el => el.source)但这当然行不通，因为find只会给我一个结果（这是一个对象）。如何获得所有结果而不是第一个匹配的对象？

Answer 1

而不是使用Array.find，您需要使用Array.filter来获得匹配的结果。

const deps = {

  "something": [

    {

      "type": "static",

      "source": "foo",

      "target": "bar"

    },

    {

      "type": "static",

      "source": "return-me",

      "target": "find-me"

    }

  ],

  "anything": [

    {

      "type": "static",

      "source": "and-me",

      "target": "find-me"

    }

  ],

  "no-match": [

    {

      "type": "static",

      "source": "foo",

      "target": "bar"

    }

  ]

};

const result = Object.values(deps)

  .flat()

  .filter(({ target }) => target === 'find-me')

  .map(({ source }) => source);

console.log(result);

Answer 2

替换Array.find()为Array.filter()可以返回多个结果：

const deps = {"something":[{"type":"static","source":"foo","target":"bar"},{"type":"static","source":"return-me","target":"find-me"}],"anything":[{"type":"static","source":"and-me","target":"find-me"}],"no-match":[{"type":"static","source":"foo","target":"bar"}]}

const search = 'find-me'

const sources = Object

  .values(deps)

  .flat()

  .filter(el => el.target === search)

  .map(el => el.source)

  

console.log(sources)