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TA贡献1824条经验 获得超5个赞
当您的脚本试图对其执行某些操作的元素的属性发生更改时,会发生陈旧元素异常。如果你想点击带有文本“XXX”的跨度,你可以直接点击它:
WebDriverWait(driver, 20).until(EC.presence_of_element_located((By.XPATH, "//a[span[text()='XXX']]")))
如果您的要求是遍历所有这些元素,那么:
connections=driver.find_elements_by_css_selector("a span[class='mn-connection-card__name t-16 t-black t-bold']")
print(len(connections))
for i in range(len(connections)):
connections=driver.find_elements_by_css_selector("a span[class='mn-connection-card__name t-16 t-black t-bold']") #Created Fresh element list, so it wont be stale
if connections[i].text == "XXX"
connections[i].click
break
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