获取函数内字符串的值

Question

所以就有了这个函数：function rpress_get_service_types() {  $service_types = array(    'delivery'  => __( 'Delivery', 'restropress' ),    'pickup'    => __( 'Pickup', 'restropress' )  );  return apply_filters( 'rpress_service_type', $service_types );}我想从中获得价值。比方说，是'delivery'还是'pickup'？然后，我需要知道整个代码引用的产品是否设置为 or 'pickup'-'delivery'每个产品仅分配给这两个值之一。因此，在我尝试验证它是否与这两个值之一匹配之前，我想我应该将其打印在我发送给自己的测试电子邮件中......以查看它是否有效。下面的代码返回The order #2262 is ready for delivery!Arraytest我作为测试收到的电子邮件的值：function send_customer_purchase_notification_ready( $payment_id, $new_status ) {    $pickup_or_delivery = rpress_get_service_types( $service_types );    $order_status = rpress_get_option( $new_status );    $check_notification_enabled = isset( $order_status['enable_notification'] ) ? true : false;    if ( !empty( $payment_id ) && $check_notification_enabled && $new_status !== 'pending' && $new_status == 'ready' ) {                          $message = 'The order #' .$payment_id. ' is ready for delivery!' .$pickup_or_delivery. 'test';        $to = '[e-mail]';        $subject = "READY FOR PICKUP";        $headers = '';         //Here put your Validation and send mail        $sent = wp_mail($to, $subject, strip_tags($message), $headers);    }}add_action( 'rpress_update_order_status', 'send_customer_purchase_notification_ready' , 10, 2 );正如你所看到的，我将变量放在里面$message = 'The order #' .$payment_id. ' is ready for delivery!' .$pickup_or_delivery. 'test';总结一下：此代码显示单词Array。我已经尝试移动东西好几个小时了，但我感觉自己在撞墙。有任何想法吗？

Answer 1

如您所见，rpress_get_service_types()将会返回一个数组，因此$pickup_or_delivery是一个数组。

您不能将字符串The order #2262 is ready for delivery!..与数组连接起来。如果需要，您应该使用implode将数组转换为字符串，或者使用ob_get_clean获取缓冲区内容

$pickup_or_delivery = rpress_get_service_types();

// get the imploded version

$pickup_or_delivery = implode(',', $pickup_or_delivery);

// or get the buffer content

ob_start();

print_r($pickup_or_delivery);

$pickup_or_delivery = ob_get_clean();

Answer 2

使用以下代码获取“服务类型”：

$service_type = rpress_get_service_type( $payment_id );