我侄女在学校做作业时问我这个问题，我不知道该怎么做。老师要求他们在 java 中使用 3 个 for 循环打印以下模式：1******12*****123****1234***12345**123456*1234567请帮忙。谢谢！
3 回答
慕盖茨4494581
TA贡献1850条经验 获得超11个赞
这曾经是我的家庭作业
代码
for (int i = 1; i <= 7; i++) {
for (int j = 1; j <= i; ++j) {
System.out.print(j);
}
System.out.println("");
}
将会呈现
1
12
123
1234
12345
123456
1234567
和
for (int i = 1; i <= 7; i++) {
for (int k = 7 - i; k >= 1; k--) {
System.out.print("*");
}
System.out.println("");
}
将会呈现
******
*****
****
***
**
*
最终的
for (int i = 1; i <= 7; i++) {
for (int j = 1; j <= i; ++j) {
System.out.print(j);
}
for (int k = 7 - i; k >= 1; k--) {
System.out.print("*");
}
System.out.println("");
}
将会呈现
1******
12*****
123****
1234***
12345**
123456*
1234567
回首忆惘然
TA贡献1847条经验 获得超11个赞
public static void printPattern(int n) {
for(int i=0; i<n; i++) {
for(int k=1; k<=i+1; k++) {
System.out.print(k);
}
for(int j=i+1; j<n; j++) {
System.out.print("*");
}
System.out.println("");
}
}
MYYA
TA贡献1868条经验 获得超4个赞
Are you sure question has been asked to solve by using 3 for loops?
As it is better to use less loop as much as we can. Secondly there is no requirement in problem to use third loop. you can find the desired result by using two loops:
public class Main
{
public static void main(String[] args) {
for (int i = 1; i <= 7; i++) {
for (int j = 1; j <= 7; j++) {
if (j <= i) {
System.out.print(j);
}
else
{
System.out.print("*");
}
}
System.out.println("\n");
}
}
}
output will be:
1******
12*****
123****
1234***
12345**
123456*
1234567
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