如何在Python中将列表中的字符串替换为int？

Question

在下面的列表中，我想将“Sun”替换为 0，将“Rain”替换为 1。我该怎么做？precipitation = ["Sun", "Rain", "Rain", "Sun", "Sun", "Sun", "Sun", "Sun", "Sun", "Sun", "Rain", "Rain", "Rain", "Rain"]for i in precipitation:    if precipitation[i] == "Sun":    precipitation[i] = 0  else:    precipitation[i] = 1

Answer 1

您可以使用列表理解来做到这一点：

precipitation = [0 if x == 'Sun' else 1 for x in precipitation]

Answer 2

使用布尔值用数字表示为 0 和 1 的事实来详细阐述 @Gabip 的答案：

[int(x=='Sun') for x in precipitation]

Answer 3

添加到已经存在的答案中，使用map()

list(map(lambda x: 0 if x=='Sun' else 1,a))

您可以尝试这样做以避免循环和列表理解

Answer 4

尝试这个...

precipitation = ["Sun", "Rain", "Rain", "Sun", "Sun", "Sun", "Sun", "Sun", "Sun", "Sun", "Rain", "Rain", "Rain", "Rain"]

for i in range(len(precipitation)):  

  if precipitation[i] == "Sun":

    precipitation[i] = 0

  else:

    precipitation[i] = 1

         

print(precipitation)