循环内有超时的for循环？

我试图找到一种方法来进行for循环，如果for循环的迭代次数超过超时时间，则它会中断并转到下一次迭代。例子：timeout = 60for i in mylist: i += 1 if time > timeout: break

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2 回答

当年话下

TA贡献1890条经验获得超9个赞

我认为您可以使用时间模块，如下所示：

import time

#get the time at the start of the program

x = time.localtime(time.time())

start_time = time.strftime('%S', x)

#the loop

timeout = 5

for i in range(10000000):

i += 1

y = time.localtime(time.time())

now_time = time.strftime('%S', y)

run_time = int(now_time) - int(start_time)

print(run_time) #to see the run_time

if run_time > timeout:

break

反对回复 2023-06-20

一只名叫tom的猫

TA贡献1906条经验获得超2个赞

假设单次迭代不需要那么多，只需使用time模块和 while 循环，如下所示：

mylist = [1,2,3]

import time

timeout = 60

time_start = time.time()

i = 0

while i < len(mylist) and time.time() - time_start < timeout:

# do your stuff

i += 1

if i == len(mylist):

# this code runs if the iteration has completed, pass does nothing

pass

else:

# and this code runs if there was a timeout

pass

反对回复 2023-06-20

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