这是代码：dict1 = {"games" : ["football", "cricket"]}print(dict1)input1 = input("enter key : ")input2 = input("enter value : ")dict1[input1].pop(input2)它给出的输出为：'games': ['football', 'cricket']}enter key : gamesenter value : footballTraceback (most recent call last): File "C:/Users/fateo/PycharmProjects/pythonTuts/10Dictionary.py", line 116, in <module> dict1[input1].pop(input2)TypeError: 'str' object cannot be interpreted as an integerProcess finished with exit code 1它与附加一起工作正常dict1[input1].append(input2)即使我尝试使用 for 循环：for key, values in dict1.items(): values.pop(input2)它给出的错误为：{'games': ['football', 'cricket']}enter key : gamesenter value : footballTraceback (most recent call last): File "C:/Users/fateo/PycharmProjects/pythonTuts/10Dictionary.py", line 113, in <module> values.pop(input2)TypeError: 'str' object cannot be interpreted as an integerProcess finished with exit code 1当我使用 (int) 时：input2 = int(input("enter value : "))它给出的错误为Traceback (most recent call last): File "C:/Users/fateo/PycharmProjects/pythonTuts/10Dictionary.py", line 110, in <module> input2 = int(input("enter value : "))ValueError: invalid literal for int() with base 10: 'football'我也用了deldel dict1[input2]它说TypeError: 'str' object cannot be interpreted as an integer我不明白为什么它把它解释为整数
3 回答
Smart猫小萌
TA贡献1911条经验 获得超7个赞
不要使用pop尝试这个代替。
dict1 = {"games" : ["football", "cricket"]}
print(dict1)
input1 =input("enter key : ")
input2 = input("enter value : ")
for value in dict1.values():
if (input2) in value:
value.remove(input2)
print(dict1)
慕莱坞森
TA贡献1810条经验 获得超4个赞
您不能使用pop带有字符串值作为参数的 on 列表。需要pop要删除的元素的索引。
因为你的字典只有一个键，所以最简单的方法就是字典理解：
{k: [x for x in v if x != input2] for k, v in dict1.items() if k == input1}
..您的示例中的内容如下所示：
dict1 = {"games" : ["football", "cricket"]}
print(dict1)
input1 = input("enter key : ")
input2 = input("enter value : ")
print({k: [x for x in v if x != input2] for k, v in dict1.items() if k == input1})
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