我面临与搜索 JQL 相关的问题。我正在使用查询(issuefunction in issuesInEpics('key = ABCD-24911') and issuetype=Feature)在 Jira 中，它返回一些记录，但是当我在其中使用此查询时，JiraRestClient它不起作用，而是返回零记录。它对于以下查询工作正常：issuefunction in issuesInEpics("resolution is not empty") and issuetype = Feature代码片段：String query="issuefunction in issuesInEpics('key = ABCD-24911') and issuetype=Feature"; Integer resultsLength=50,startAt=0; JiraRestClient.getSearchClient().searchJql(query,resultsLength,startAt,null);我的 Maven 依赖项：<dependency> <groupId>com.atlassian.jira</groupId> <artifactId>jira-rest-java-client-api</artifactId> <version>4.0.0</version> </dependency> <dependency> <groupId>com.atlassian.jira</groupId> <artifactId>jira-rest-java-client-core</artifactId> <version>4.0.0</version> </dependency> <dependency> <groupId>com.atlassian.fugue</groupId> <artifactId>fugue</artifactId> <version>2.2.1</version> </dependency> <dependency> <groupId>com.atlassian.httpclient</groupId> <artifactId>atlassian-httpclient-spi</artifactId> <version>0.17.0-m01</version> </dependency>任何人请帮助我找到解决方案。
2 回答
慕后森
TA贡献1802条经验 获得超5个赞
我认为可能是您的 JIRA 实例特有的问题导致了您的问题。我下面的代码基于 Anish 编写的内容。它编译并运行得非常好，打印出我期望它显示的确切问题列表。
当您可以并排查看两段代码时，这可能会对您有所帮助。
public static void main(String[] args) throws URISyntaxException {
URI uri = new URI("https://example.com");
JiraRestClientFactory jiraRestClientFactory = new AsynchronousJiraRestClientFactory();
try (JiraRestClient jiraRestClient = jiraRestClientFactory.createWithBasicHttpAuthentication(uri, "email", "password")) {
SearchRestClient searchClient = jiraRestClient.getSearchClient();
String query = "issueFunction in issuesInEpics('key = PROJ-1234') and issuetype = Task";
System.out.println(query);
SearchResult result = searchClient.searchJql(query, 50, 0, null).claim();
for (Issue issue : result.getIssues()) {
System.out.println(issue.getKey());
}
} catch (Exception ex) {
ex.printStackTrace();
}
}
我还使用我公司使用的自定义代理客户端尝试了给定的 JQL，并且查询绝对工作得很好。请检查您的环境和 JIRA 日志..
LEATH
TA贡献1936条经验 获得超6个赞
解决方法是使用
String query="issueFunction in linkedIssuesOf('key=ABCD-24911', 'is epic of')
AND issuetype=Feature";代替
String query="issuefunction in issuesInEpics('key = ABCD-24911')
AND issuetype=Feature";背景：它看起来像功能IssuesInEpics()，epicsOf()最近才引入以修改linkedIssuesOf().
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