我有两个这样的数组：let event = [ {id: "123", ename: "abc"} {id: "125", ename: "def"} ]let speaker = [ {id: "11", sname: "s1", event_id: "123"}, //FK from event table {id: "13", sname: "s2", event_id: "123"}, {id: "15", name: "s4", event_id: "125"} ]我想要这样的输出：let event_speaker = [ { id: "123", ename: "abc", speaker: [ {id: "11", sname: "s1", event_id: "123"}, {id: "13", sname: "s2", event_id: "123"}, ] }, { id: "125", ename: "def", speaker: [ {id: "15", sname: "s4", event_id: "125"} ] } ]我尝试了不同的答案，这些答案可以将两个数组合并为一个，但当我们有多个匹配对并且我需要用我自己的密钥（扬声器）将其放入一个新数组时，则不行。我已经尝试过这个：let arr3 = arr1.map((item, i) => Object.assign({}, item, arr2[i]));但它只适用于一个扬声器，因为它将所有扬声器键放入最终数组中，如下所示let final_array = [ id: "123", ename: "abc, sname: "s1", event_id: "123"]
2 回答
噜噜哒
TA贡献1784条经验 获得超7个赞
您可以使用map和filter方法来做到这一点。您只需要speaker使用 中当前元素的 id 过滤数组event。
let event = [{"id":"123","ename":"abc"},{"id":"125","ename":"def"}]
let speaker = [{"id":"11","sname":"s1","event_id":"123"},{"id":"13","sname":"s2","event_id":"123"},{"id":"15","name":"s4","event_id":"125"}]
const event_speaker = event.map(({ id, ...rest }) => ({
id, ...rest, speaker: speaker.filter(({ event_id }) => event_id === id)
}))
console.log(event_speaker)
慕田峪9158850
TA贡献1794条经验 获得超7个赞
您也可以使用对象破坏：
let event = [
{id: "123", ename: "abc"},
{id: "125", ename: "def"}
]
let speaker = [
{id: "11", sname: "s1", event_id: "123"}, //FK from event table
{id: "13", sname: "s2", event_id: "123"},
{id: "15", name: "s4", event_id: "125"}
]
let result = event.map(e => ({...e,speaker: speaker.filter(({event_id}) => event_id === e.id)}))
console.log(result)
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