我有 JSON 数据，想通过键更新值。JSON：{ "language":"en", "education":[ { "unit":"e1", "language":"en" } ], "membership":[ { "uei":"21", "Uifed":"failed" } ]}我想将“失败”的值更改uifed为“成功”。我做了什么？$json = '{"language":"en","education":[{"unit":"e1","language":"en"}],"membership":[{"uei":"21","Uifed":"failed"}]}';$arrayData = json_decode($json, true);$replacementData = array('Uifed' => 'success');$newArrayData = array_replace_recursive($arrayData, $replacementData);echo var_dump($newArrayData);结果：NULL我怎样才能做到这一点？
2 回答
鸿蒙传说
TA贡献1865条经验 获得超7个赞
事情不是这样的array_replace_recursive；替换数组需要与您要替换的数组具有相同的结构。对于您的示例数据，这将起作用：
$json = '{"language":"en","education":[{"unit":"e1","language":"en"}],"membership":[{"uei":"21","Uifed":"failed"}]}';
$arrayData = json_decode($json, true);
$replacementData = array('membership' => array(array('Uifed' => 'success')));
$newArrayData = array_replace_recursive($arrayData, $replacementData);
print_r($newArrayData);
输出：
Array
(
[language] => en
[education] => Array
(
[0] => Array
(
[unit] => e1
[language] => en
)
)
[membership] => Array
(
[0] => Array
(
[uei] => 21
[Uifed] => success
)
)
)
array_walk_recursive可以用来做你想做的事：
$replacementData = array('Uifed' => 'success');
array_walk_recursive($arrayData, function (&$value, $key) use ($replacementData) {
$value = $replacementData[$key] ?? $value;
});
print_r($arrayData);
输出：
Array
(
[language] => en
[education] => Array
(
[0] => Array
(
[unit] => e1
[language] => en
)
)
[membership] => Array
(
[0] => Array
(
[uei] => 21
[Uifed] => success
)
)
)
慕标琳琳
TA贡献1830条经验 获得超9个赞
通过引用foreach传递值的简单示例：
$json = '{"language":"en","education":[{"unit":"e1","language":"en"}],"membership":[{"uei":"21","Uifed":"failed"}]}';
$arrayData = json_decode($json, true);
foreach ($arrayData['membership'] as &$membership) {
if ('failed' === $membership['Uifed']) {
$membership['Uifed'] = 'success';
}
}
print_r($arrayData);
小提琴。
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