我正在尝试抓取此网站上的排名表：https ://www.timeshighereducation.com/world-university-rankings/2021/world-ranking#!/page/0/length/25/sort_by/scores_overall/sort_order /asc/cols/分数但我无法获取数据，现在我有这个代码：import scrapyfrom scrapy import Selectorfrom selenium import webdriverfrom selenium.webdriver.common.by import Byfrom selenium.webdriver.support.ui import WebDriverWaitfrom selenium.webdriver.support import expected_conditions as ECfrom logzero import logfile, loggerclass ScrapeTableSpider(scrapy.Spider):    name = "scrape-table"    allowed_domains = ["toscrape.com"]    start_urls = ['http://quotes.toscrape.com']    def start_requests(self):        # headers = {'User-Agent': 'Mozilla/5.0 (X11; Linux x86_64; rv:48.0) Gecko/20100101 Firefox/48.0'}        for url in self.start_urls:            yield scrapy.Request(url=url, callback=self.parse)    def parse(self, response):        # driver = webdriver.Chrome()        options = webdriver.ChromeOptions()        options.add_argument("headless")        desired_capabilities = options.to_capabilities()        driver = webdriver.Chrome('C:/chromedriver', desired_capabilities=desired_capabilities)        driver.get("https://www.timeshighereducation.com/world-university-rankings/2021/world-ranking#!/page/0/length/25/sort_by/scores_overall/sort_order/asc/cols/scores")        driver.implicitly_wait(2)        for table in driver.find_element_by_xpath('//*[contains(@id,"datatable-1")]//tr'):            data = [item.text for item in table.find_elements_by_xpath(".//*[self::td or self::th]")]            print(data)任何有关如何从表中获取数据的见解将不胜感激。