我尝试发送POST带有这样的正文的请求{ "method": "getAreas", "methodProperties": { "prop1" : "value1", "prop2" : "value2", }}这是我的代码static final String HOST = "https://somehost.com"; public String sendPost(String method, Map<String, String> methodProperties) throws ClientProtocolException, IOException { HttpPost post = new HttpPost(HOST); List<NameValuePair> urlParameters = new ArrayList<>(); urlParameters.add(new BasicNameValuePair("method", method)); List<NameValuePair> methodPropertiesList = methodProperties.entrySet().stream() .map(entry -> new BasicNameValuePair(entry.getKey(), entry.getValue())) .collect(Collectors.toList()); // ??? urlParameters.add(new BasicNameValuePair("methodProperties", methodPropertiesList)); post.setEntity(new UrlEncodedFormEntity(urlParameters)); try (CloseableHttpClient httpClient = HttpClients.createDefault(); CloseableHttpResponse response = httpClient.execute(post)) { return EntityUtils.toString(response.getEntity()); } }但 的构造函数BasicNameValuePair适用(String, String)。所以我需要另一堂课。有什么办法可以添加methodPropertiesList吗urlParameters？
3 回答
长风秋雁
TA贡献1757条经验 获得超7个赞
您的请求看起来像 json 结构，因此发布如下数据：
class pojo1{
String method;
Map<String,String> methodProperties;
}
String postUrl = "www.site.com";// put in your url
Gson gson = new Gson();
HttpClient httpClient = HttpClientBuilder.create().build();
HttpPost post = new HttpPost(postUrl);
StringEntity postingString = new StringEntity(gson.toJson(pojo1));//gson.tojson() converts your pojo to json
post.setEntity(postingString);
post.setHeader("Content-type", "application/json");
HttpResponse response = httpClient.execute(post);
慕无忌1623718
TA贡献1744条经验 获得超4个赞
对于这个问题有一个众所周知的方法。在大多数情况下，您将创建自己的对象来描述要在 HttpPost 中发送的内容。所以你会得到类似的东西：
static final String HOST = "https://somehost.com";
public String sendPost(String method,
Map<String, String> methodProperties) throws ClientProtocolException, IOException {
HttpPost post = new HttpPost(HOST);
MyResource resource = new MyResource();
resource.setMethod(method);
MyNestedResource nestedResource = new MyNestedResource();
nestedResource.setMethodProperties(methodProperties);
resource.setNestedResourceMethodProperties(nestedResource);
StringEntity strEntity = new StringEntity(gson.toJson(resource));
post.setEntity(strEntity);
try (CloseableHttpClient httpClient = HttpClients.createDefault();
CloseableHttpResponse response = httpClient.execute(post)) {
return EntityUtils.toString(response.getEntity());
}
}
这通常是您使用嵌套结构处理更复杂的 json 对象的方式。您必须为要发送的资源创建类（在您的示例中，它可能是一个类并在其中使用映射，但通常您也为嵌套对象创建一个类，如果它具有特定的结构）。
慕妹3146593
TA贡献1820条经验 获得超9个赞
static final String HOST = "https://somehost.com";
public String sendPost(String method, Map<String, String> methodProperties) throws ClientProtocolException, IOException {
HttpPost post = new HttpPost(HOST);
Gson gson = new Gson();
Params params = new Params(method, methodProperties);
StringEntity entity = new StringEntity(gson.toJson(params));
post.setEntity(entity);
try (CloseableHttpClient httpClient = HttpClients.createDefault();
CloseableHttpResponse response = httpClient.execute(post)) {
return EntityUtils.toString(response.getEntity());
}
}
class Params {
String method;
Map<String, String> methodProperties;
public Params(String method, Map<String, String> methodProperties) {
this.method = method;
this.methodProperties = methodProperties;
}
//getters
}
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