最新回答 / 阿韵仔
def func(L): sum1=0 acc1=1 if(isinstance(L,list)): for x in L: sum1=sum1+x return sum1 if(isinstance(L,tuple)): for y in L: acc1=acc1*y return acc1L1=[1,3,4,6,2,9]L2=(1,3)a=func(L1)b=func(L2)pr...
2021-12-13
最赞回答 / weixin_慕慕3548851
在Python中，确实可以使用`del`关键字来删除字典中的元素，例如：```pythonmy_dict = {'a': 1, 'b': 2, 'c': 3}del my_dict['b'] # 删除键为'b'的元素```这种方法通常是直接而有效的，特别是当您知道要删除的键时。但有时候，使用其他方式删除字典中的元素可能更有用，具体取决于您的需求和情况：1. **字典的`pop()`方法：** 您可以使用`pop()`方法来删除字典中的元素，并且可以在元素不存在时提供一个默认值。例如： ```pyth...
2021-12-10
sum = 1
num = 1
while num <=10:
sum=sum*num
num=num+1
print(sum)
num = 1
while num <=10:
sum=sum*num
num=num+1
print(sum)
2021-12-10
L = [75, 92, 59, 68, 99]
sum = 0.0
for a in L:
sum=sum+a
print(sum/len(L))
sum = 0.0
for a in L:
sum=sum+a
print(sum/len(L))
2021-12-10
最赞回答 / qq_慕婉清6326688
d = {'Alice': [45],'Bob': [60],'Candy': [75]}l = ([50, 61, 66],[80, 61, 66],[88, 75, 90])n = ['Alice','Bob','Candy']num = 0for x in n: for z in l[num]: d[x].append(z) num += 1print(d)
{'Alice': [45, 50, 61, 66], 'Bob': [60, 80, 61, 66], 'Can...
2021-12-09
x=(1,5,8,4)
def func(x):
if isinstance(x,list):
sum=0
for a in x:
sum=sum+a
return sum
if isinstance(x,tuple):
ji=1
for a in x:
ji=ji*a
return ji
print(func(x))
def func(x):
if isinstance(x,list):
sum=0
for a in x:
sum=sum+a
return sum
if isinstance(x,tuple):
ji=1
for a in x:
ji=ji*a
return ji
print(func(x))
2021-12-08
l=[1, 4, 5, 7, 9, 11]
def sub_sum(l):
suma=0
sumb=0
for a in l:
if a % 2 ==0:
suma=suma+a
else:
sumb=sumb+a
return suma,sumb
result=sub_sum(l)
print('偶数项和={}'.format(result[0]))
print('奇数项和={}'.format(result[1]))
def sub_sum(l):
suma=0
sumb=0
for a in l:
if a % 2 ==0:
suma=suma+a
else:
sumb=sumb+a
return suma,sumb
result=sub_sum(l)
print('偶数项和={}'.format(result[0]))
print('奇数项和={}'.format(result[1]))
2021-12-08
abc = 'Life is short,{}'
youneedPython = 'you need Python'
result = abc.format(youneedPython)
print(result)
youneedPython = 'you need Python'
result = abc.format(youneedPython)
print(result)
2021-12-08
已采纳回答 / weixin_慕前端4435978
因为第一行 template = 'Hello {w}, Hello {c}, Hello {b}, Hello {i}.' 里面的w,c,b,i是给该模板位置的代号名称，而不能作为一个变量，为了不重复，建议将下面赋值语句的变量名进行修改，如s1 = 'World's2 = 'China's3 = 'Beijing's4 = 'imooc'然后最后赋值给模块中的位置result = template.format(w=s1,c=s2,b=s3,i=s4）最后要记得打印出来print(result)💪
2021-12-07
x=[1,2,5,6,8]
def square_of_sum(x):
result=0
l=[]
for num in x:
result=num*num
l.append(result)
result=sum(l)
return result
m=square_of_sum(x)
print(m)
def square_of_sum(x):
result=0
l=[]
for num in x:
result=num*num
l.append(result)
result=sum(l)
return result
m=square_of_sum(x)
print(m)
2021-12-06
# Enter a code
s1 = set([1, 2, 3, 4, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
if s1.isdisjoint(s2) != True:
for a in s1:
if a in s2:
print(a)
s1 = set([1, 2, 3, 4, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
if s1.isdisjoint(s2) != True:
for a in s1:
if a in s2:
print(a)
2021-12-06
最新回答 / 慕圣8481703
cube[0]对应的是当前循环到的长方体list中的长，cube[1]是当前循环的长方体list中的宽，cube[2]是当前循环的长方体list中的高也可以这么理解。
2021-12-06
