num1=3.14
num2=1.57
a=num1*num2
print(round(a)) #==>4.93
num2=1.57
a=num1*num2
print(round(a)) #==>4.93
2021-11-18
最赞回答 / 是小丹泓呀
# Enter a coded = {'Alice': [50, 61, 66], 'Bob': [80, 61, 66], 'Candy': [88, 75, 90]}m = 0for key in d.keys(): m += 1print(m)n = 0for x in d: n = n + 1 print(x) #打印出来看看print(n)y = 0for s in d.values(): y += 1 print(s)print(y)感觉可以
2021-11-16
# Enter a code
def square_of_sum(l):
sum=0
for x in l:
sum=sum+x*x
return(sum)
print(square_of_sum([2,6,4,5]))
def square_of_sum(l):
sum=0
for x in l:
sum=sum+x*x
return(sum)
print(square_of_sum([2,6,4,5]))
2021-11-13
# 要查找的姓名转换成小写，遍历的集合时，将成员也转换成小写，再遍历
names = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
name_set = set(names)
namesInput = "ALICE".lower()
for name in name_set:
if namesInput == name.lower():
print("cun zai")
break #找到姓名时，就跳出循环
else:
print("mei you zhao dao")
names = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
name_set = set(names)
namesInput = "ALICE".lower()
for name in name_set:
if namesInput == name.lower():
print("cun zai")
break #找到姓名时，就跳出循环
else:
print("mei you zhao dao")
2021-11-10