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  • n=100
    while n<999:
       i=int(n/100)
       j=int(n/10%10)
       k=int(n%10)
       result=i*i*i+j*j*j+k*k*k
       if n==result:
           print(n)
       n=n+1
    print("所有的水仙花数")

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  • .append(数据)#函数,追加一个元素放到列表最后

    books.append("儒林外史")#插到最后一排

    .insert(索引,数据)#插入一个元素到列表相应位置

    books.append(4,"儒林外史")#插到第5个

    books[4]='儒林外史"#更新一个数据,列表[4]=新数据

    列表.pop(索引)#删除数据

    books.pop(4)#删除books第5个数据

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    0 采集 收起 来源:调整数据操作

    2022-03-12

  • if 判断条件 :

          python语句1

    elif 判断条件 :

          python语句2

    else:

          python语句3

    多重分支,前面的条件如果符合一条,后面的判断都会取消

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    0 采集 收起 来源:多分支判断

    2022-03-12

  • not or and 

    not级别最高

    or次之

    and最低

    not(),先判断()里,如果是True,结果就是Flase

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    0 采集 收起 来源:逻辑运算符

    2022-03-12

  • # coding=utf-8

    movies = []

    mov = {"year":1902,"title":"月球之旅","director":"乔治斯·梅利斯","description":"历史上第一部科幻电影"}

    movies.append(mov)

    mov1 = {"year":1916,"title":"海底两万里","director":"查理德·弗莱彻","description":"第一步水下拍摄的科幻电影"}

    movies.append(mov1)


    y = 1916

    for m in movies:

        if y == m["year"]:

            print(m["year"])

            print(m["title"])

            print(m["director"])

            print(m["description"])

    http://img1.sycdn.imooc.com//609553bc000115d402960128.jpg

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  • # coding=utf-8

    col1 = ["玩具","饮料","唇彩"]

    col2 = ["手办","卡片","唇彩"]

    col3 = ["卡片","饮料","手套"]

    row = [col1,col2,col3]


    for col in row:

        for box in col:

            print(box)

        print("==============")

    http://img1.sycdn.imooc.com//609550ad000110a603300258.jpg

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    0 采集 收起 来源:嵌套循环

    2021-05-07

  • #while

    # coding=utf-8

    n = 100

    while n < 1000:

        i = int(n/100)

        j = int(n/10)%10

        k = n %10

        if n == i*i*i+j*j*j+k*k*k:

            print(n,end="")

            print("是水仙花数")

        n = n+1

    http://img1.sycdn.imooc.com//60954e0d00018a1302630124.jpg

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  • # coding=utf-8


    for n in range(100,1000):

        i = int(n/100)

        j = int(n/10)%10

        k = n %10

        if n == i*i*i+j*j*j+k*k*k:

            print(n,end="")

            print("是水仙花数")

    http://img1.sycdn.imooc.com//60954d830001eacc02230125.jpg

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  • #range 左闭右开

    # coding=utf-8

    for i in range(10,15):

        print(i)

    http://img1.sycdn.imooc.com//60954b6b0001f15a02440164.jpg

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  • # coding=utf-8

    books = ["三国演义","水浒传","西游记"]

    for book in books:

        if book != "西游记":

            print(book)

    http://img1.sycdn.imooc.com//60954ac80001042202470093.jpg

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  • # coding=utf-8

    i = 1

    res = 3

    while i <= 10 :

        print(res)

        res = res * 3

        i = i + 1 

    print("循环结束")

    http://img1.sycdn.imooc.com//609549930001bc7603940231.jpg

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  • # coding=utf-8

    i= 0

    while i < 4:

        print(i*100)

        i = i+1

    print("循环结束")


    http://img1.sycdn.imooc.com//609548c50001325a02640168.jpg

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  • 列表字典组合

    # coding=utf-8

    stus = []

    stu1 = {"no":"111","name":"张三","age":23,"nation":"汉","birthday":"1998-01-01","father":{"name":"张建国","company":"中国移动","job":"客户经理"},"mother":{"name":"吴燕玲","company":"师大附中","job":"语文老师"}}

    stus.append(stu1)

    print(stus)

    name = stus[-1]["name"]

    print(name)


    stu2 = {"no":"112","name":"李四","age":23,"nation":"汉","birthday":"1998-01-01","father":{"name":"李建国","company":"中国联通","job":"客户经理"},"mother":{"name":"张丽丽","company":"人民医院","job":"外科医生"}}

    stus.append(stu2)

    print(stus)


    name = stus[-1]["name"]

    print(name)

    fatherName = stus[-1]["father"]["name"]

    print(fatherName)

    http://img1.sycdn.imooc.com//6095464100019eea19080167.jpg

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  • 列表字典组合

    # coding=utf-8

    stus = []

    stu1 = {"no":"111","name":"张三","age":23,"nation":"汉","birthday":"1998-01-01","father":{"name":"张建国","company":"中国移动","job":"客户经理"},"mother":{"name":"吴燕玲","company":"师大附中","job":"语文老师"}}

    stus.append(stu1)

    print(stus)

    name = stus[-1]["name"]

    print(name)


    stu2 = {"no":"112","name":"李四","age":23,"nation":"汉","birthday":"1998-01-01","father":{"name":"李建国","company":"中国联通","job":"客户经理"},"mother":{"name":"张丽丽","company":"人民医院","job":"外科医生"}}

    stus.append(stu2)

    print(stus)


    name = stus[-1]["name"]

    print(name)

    fatherName = stus[-1]["father"]["name"]

    print(fatherName)

    http://img1.sycdn.imooc.com//6095464100019eea19080167.jpg

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  • 列表字典组合

    # coding=utf-8

    stus = []

    stu1 = {"no":"111","name":"张三","age":23,"nation":"汉","birthday":"1998-01-01","father":{"name":"张建国","company":"中国移动","job":"客户经理"},"mother":{"name":"吴燕玲","company":"师大附中","job":"语文老师"}}

    stus.append(stu1)

    print(stus)

    name = stus[-1]["name"]

    print(name)


    stu2 = {"no":"112","name":"李四","age":23,"nation":"汉","birthday":"1998-01-01","father":{"name":"李建国","company":"中国联通","job":"客户经理"},"mother":{"name":"张丽丽","company":"人民医院","job":"外科医生"}}

    stus.append(stu2)

    print(stus)


    name = stus[-1]["name"]

    print(name)

    fatherName = stus[-1]["father"]["name"]

    print(fatherName)

    http://img1.sycdn.imooc.com//6095464100019eea19080167.jpg

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