2 回答

TA贡献1842条经验 获得超13个赞
在您的post.php中,您可以简单地回显数组,jQuery 应该自动将其转换array为响应
// post.php
<?php
@include('../../_partials/_dbConnect.php');
$region = $_POST['region'];
$district = $_POST['district'];
$sql = "SELECT * FROM table1 WHERE name_rg= '".$region."'";
$result = pg_query($db_connection, $sql);
while ($row = pg_fetch_row($result)) {
$cols = array($row[0],$row[1],$row[2],$row[3],$row[4],$row[5],$row[6],$row[7],$row[8],$row[9],$row[10],$row[11],$row[12],$row[13],$row[14],$row[15],$row[16],$row[17],$row[18],$row[19],$row[20],$row[21]);
}
echo json_encode($cols);
?>
// Somewhere in your js
$.post(
"post.php",
{
region: region,
district: district
},
function(data) {
console.log(data[0]);
}
);

TA贡献1803条经验 获得超6个赞
在 javascript 中使用 JSON.parse()
$.post(
"post.php",
{
region: region,
district: district
},
function(data) {
data=JSON.parse(data);
}
);```
And here you go, u can play with it as you need
Happy learning!
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