#coding=utf-8
age=18
if age>=18:
print('成年')
elif age>=6 and age<=17:
print('青少年')
elif age>=3 and age<6:
print('小孩')
else:
print('婴儿')
age=18
if age>=18:
print('成年')
elif age>=6 and age<=17:
print('青少年')
elif age>=3 and age<6:
print('小孩')
else:
print('婴儿')
2021-06-29
score = [95.5, 85, 59, 66,72]
sub_score = score[0:3]
print(sub_score)
sub_score = score[0:3]
print(sub_score)
2021-06-29
L = ['Alice', 66, 'Bob', True, 'False', 100]
count = 0
for goods in L :
if count %2 == 0:
print(goods)
count = count + 1
count = 0
for goods in L :
if count %2 == 0:
print(goods)
count = count + 1
2021-06-29
L = [75, 92, 59, 68, 99]
sum = 0
for ch in L:
sum = sum+ch
print(sum/5)
sum = 0
for ch in L:
sum = sum+ch
print(sum/5)
2021-06-28
可以试一下这个，结果一样，但意思是直接创建新的元素和数据。
d = dict()
d['Alice']=[50,61,60]
d['Bob'] = [80,61,66]
d['Candy'] = [88,75,90]
print(d)
d = dict()
d['Alice']=[50,61,60]
d['Bob'] = [80,61,66]
d['Candy'] = [88,75,90]
print(d)
2021-06-28
利用for更加简单方便
d = {
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49
}
c = ('Alice', 'Bob', 'Candy', 'Mimi', 'David')
for a in c:
print(d.get(a))
d = {
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49
}
c = ('Alice', 'Bob', 'Candy', 'Mimi', 'David')
for a in c:
print(d.get(a))
2021-06-28
# coding=utf-8
# 长方形的长为3.14厘米，宽为1.57厘米，求长方形面积，保留两位小数
a=3.14
b=1.57
A=round(a*b,2)
print('长方形的面积是'+str(A)+'平方厘米')
# 长方形的长为3.14厘米，宽为1.57厘米，求长方形面积，保留两位小数
a=3.14
b=1.57
A=round(a*b,2)
print('长方形的面积是'+str(A)+'平方厘米')
2021-06-27
已采纳回答 / 欧阳文轩
你是想求1000内偶数和吧，首先while循环条件错了，应该是b<1000；其次循环体也有问题，break在这里没有必要；还有print函数的缩进有问题。正确代码如下：一、不需要breaka = 0b = 0while(a <= 1000) : b += a a += 2print(b)二、需要breaka = 0b = 0while True : if a > 1000 : break b += a a += 2print(b)
2021-06-27
