s1 = 'ABC'
s2 = '123'
s3 = 'xyz'
for x in s1:
for y in s2:
for z in s3:
print(x+y+z)
s2 = '123'
s3 = 'xyz'
for x in s1:
for y in s2:
for z in s3:
print(x+y+z)
2021-05-12
最赞回答 / 慕仙2008175
numbersInList = [x for x in range(10)] numbersInTuple = tuple(numbersInList)
2021-05-09
最新回答 / 阿韵仔
def sum_of_jo(L): jnum=[] onum=[] jsum=0 osum=0 for x in L: if(x%2==0): onum.append(x) else: jnum.append(x) for a in jnum: jsum=jsum+a for b in onum: osum=osum+b return jsum,osumL=[...
2021-05-08
num = 0
a = 0
while num<=1000:
if num%2 == 0:
a = a + num
num = num + 1
print(a)
结果是250500对么
a = 0
while num<=1000:
if num%2 == 0:
a = a + num
num = num + 1
print(a)
结果是250500对么
2021-05-08
def square_of_sum(L):
result=0
for num in L:
result=num*num+result
return result
k=[1,2,3,4,5,6,7,8,9,10]
ss=square_of_sum(k)
print(ss)
result=0
for num in L:
result=num*num+result
return result
k=[1,2,3,4,5,6,7,8,9,10]
ss=square_of_sum(k)
print(ss)
2021-05-07
d = {'Alice': [50, 61, 66], 'Bob': [80, 61, 66], 'Candy': [88, 75, 90]}
key_idx = 0
value_idx = 0
for key in d.keys():
print(key)
for value in d.values():
print(value)
if value_idx == key_idx:
value_idx = value_idx + 1
break
key_idx = key_idx + 1
key_idx = 0
value_idx = 0
for key in d.keys():
print(key)
for value in d.values():
print(value)
if value_idx == key_idx:
value_idx = value_idx + 1
break
key_idx = key_idx + 1
2021-05-07
L1=['Alice', 'Bob', 'Candy', 'David', 'Ellena']
L2=[89, 72, 88, 79, 99]
L3=["","","","",""]
idx = 0
while idx < 5:
L3[idx] = str(L2[idx]) + L1[idx]
print(L3[idx])
idx = idx + 1
L3.sort(reverse=True)
print(L3)
idx = 0
for item in L3:
L1[idx] = item[2:10]
idx = idx+1
print(L1)
L2=[89, 72, 88, 79, 99]
L3=["","","","",""]
idx = 0
while idx < 5:
L3[idx] = str(L2[idx]) + L1[idx]
print(L3[idx])
idx = idx + 1
L3.sort(reverse=True)
print(L3)
idx = 0
for item in L3:
L1[idx] = item[2:10]
idx = idx+1
print(L1)
2021-05-06
L=['Alice', 'Bob', 'Candy', 'David', 'Ellena']
L_insert=['Zero', 'Phoebe', 'Gen']
for item in L_insert:
L.append(item)
L.sort(reverse=False)
print(L)
L_insert=['Zero', 'Phoebe', 'Gen']
for item in L_insert:
L.append(item)
L.sort(reverse=False)
print(L)
2021-05-06
num=1
advantage=1
while num<=10:
advantage=advantage*num
num=num+1
print(advantage)
advantage=1
while num<=10:
advantage=advantage*num
num=num+1
print(advantage)
2021-05-03
最赞回答 / weixin_慕侠3131023
python中，Number类型的值为不可变类型，使用round(num,2)对变量num进行的操作并不会影响到原有的变量num，所以当print(num)时，num变量的值仍然还是最初的，并不是进行了小数过滤后的值。
2021-04-30
# Enter a code
def func(X):
sum_1=0
sum_2=1
if isinstance(X,list):
for a in X:
sum_1=sum_1+a
print(sum_1)
if isinstance(X,tuple):
for b in X:
sum_2=sum_2*b
print(sum_2)
def func(X):
sum_1=0
sum_2=1
if isinstance(X,list):
for a in X:
sum_1=sum_1+a
print(sum_1)
if isinstance(X,tuple):
for b in X:
sum_2=sum_2*b
print(sum_2)
2021-04-30
# coding=utf-8
def sum_1(num):
if num==1:
return 1
return num+sum_1(num-1)
def sum_2(num):
a=1
sum=0
while(a<=num):
sum=sum+a
a=a+1
return sum
print(sum_1(100))
print(sum_2(100))
def sum_1(num):
if num==1:
return 1
return num+sum_1(num-1)
def sum_2(num):
a=1
sum=0
while(a<=num):
sum=sum+a
a=a+1
return sum
print(sum_1(100))
print(sum_2(100))
2021-04-30
