d = {
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49
}
print(d.keys())
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49
}
print(d.keys())
2021-04-11
L = [95.5, 85, 59, 66, 72]
L.sort()
print(L[-1:-4:-1])
L.sort()
print(L[-1:-4:-1])
2021-04-10
L = ['Alice', 66, 'Bob', True, 'False', 100]
print(L[1::2])
print(L[1::2])
2021-04-10
d = {
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49
}
print(d.get('Alice'))
print(d.get('Bob'))
print(d.get('Candy'))
print(d.get('David'))
print(d.get('Ellena'))
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49
}
print(d.get('Alice'))
print(d.get('Bob'))
print(d.get('Candy'))
print(d.get('David'))
print(d.get('Ellena'))
2021-04-10
最赞回答 / GrayspaceDragon
tuple 是不可变的 他是有针对性的,针对一般的数据类型,比如说 int string 但是他不针对列表,在某种意义上讲,tuple里面的list是不变的 变化的是list里面的值
2021-04-10
T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))
((1+2),)
(1, )
(1,2,3,4,5)
一共4个
((1+2),)
(1, )
(1,2,3,4,5)
一共4个
2021-04-10
score=(100, 69, 29, 100, 72, 99, 98, 100, 75, 100, 100, 42, 88, 100)
print(score.count(100))
print(score.count(100))
2021-04-10
long= [[1, 2, 3], [5, 3, 2], [7, 3, 2]]
for i in long:
s=i[0]*i[1]*i[2]
print(s)
for i in long:
s=i[0]*i[1]*i[2]
print(s)
2021-04-09
long= [[1, 2, 3], [5, 3, 2], [7, 3, 2]]
num=0
while num<3:
s=long[num][0]*long[num][1]*long[num][2]
num=num+1
print(s)
num=0
while num<3:
s=long[num][0]*long[num][1]*long[num][2]
num=num+1
print(s)
2021-04-09
name=['Alice', 'Bob', 'Candy', 'David', 'Ellena']
temp=name.pop()
name.insert(0,temp)
temp=name.pop(2)
name.append(temp)
print(name)
temp=name.pop()
name.insert(0,temp)
temp=name.pop(2)
name.append(temp)
print(name)
2021-04-09
name= ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
name.pop(2)
name.pop(2)
print(name)
name.pop(2)
name.pop(2)
print(name)
2021-04-09
name=['Alice', 'Bob', 'Candy', 'David', 'Ellena']
name.append('Phoebe')
name.append('Zero')
name.insert(5,'Gen')
print(name)
name.append('Phoebe')
name.append('Zero')
name.insert(5,'Gen')
print(name)
2021-04-09