range(var1,var2)#从var1开始，截止var2前一个数字
break 跳出循环
continue 跳过当前循环，进入下一次循环
break 跳出循环
continue 跳过当前循环，进入下一次循环
2020-11-09
var = 'AABCDEFGHHIJ'
result = var[2:-3]
print('A-H:',result)
字符串切割也可以从后向前切，最后一位字符为-1，逐渐递减-1，-2
result = var[2:-3]
print('A-H:',result)
字符串切割也可以从后向前切，最后一位字符为-1，逐渐递减-1，-2
2020-11-09
a="Hello\tWorld"
A="Hello\tWorld"
h1="Hello\tWorld"
_PY="Hello\tWorld"
print(a)
print(A)
print(h1)
print(_PY)
A="Hello\tWorld"
h1="Hello\tWorld"
_PY="Hello\tWorld"
print(a)
print(A)
print(h1)
print(_PY)
2020-11-08
# Enter a code
a=3.1415926
b='Learn Python in imooc'
c=100
d=0b1101
print(type(a))
print(type(b))
print(type(c))
print(type(d))
a=3.1415926
b='Learn Python in imooc'
c=100
d=0b1101
print(type(a))
print(type(b))
print(type(c))
print(type(d))
2020-11-08
l = [i*i for i in range(1, 101)]
sum = 0
for i in l:
sum += i
print(sum)
sum = 0
for i in l:
sum += i
print(sum)
a=0
sum=0
while True:
if a>1000:
break
elif a%2==0:
sum=sum+a
a=a+1
print(sum)
sum=0
while True:
if a>1000:
break
elif a%2==0:
sum=sum+a
a=a+1
print(sum)
2020-11-07
num =0
sum = 0
while True:
if num >1000:
break
sum = sum + num
num = num + 2
print(sum)
sum = 0
while True:
if num >1000:
break
sum = sum + num
num = num + 2
print(sum)
2020-11-06
最赞回答 / 幕布斯4328471
num = 2sum = 0while True: if num >= 1000: break sum = sum + num num = num + 2print(sum)小写t改成大写t就可以了。
2020-11-06
# Enter a code
score = 16
if score > 18:
print('adult')
else:
print('teenager')
score = 16
if score > 18:
print('adult')
else:
print('teenager')
2020-11-05