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def tuple_number_multiply(T):
multiply = 1
for num in T:
if isinstance(num, int) or isinstance(num, float):
multiply = multiply * num;
return multiply
def list_number_sum(L):
sum = 0
for num in L:
if isinstance(num, int) or isinstance(num, float):
sum = sum + num;
return sum
def func(param):
if isinstance(param, list):
return list_number_sum(param)
elif isinstance(param, tuple):
return tuple_number_multiply(param)
else:
print('param type error')
return None
def Cycle_Sum(n):
sum = 0
num = 1
while num <= n:
sum = sum + num
num = num + 1
return sum
def Recursion_Sum(n):
if n == 1:
return 1;
return n + Recursion_Sum(n - 1)
print('循环求和:{}'.format(Cycle_Sum(100)))
print('递归求和:{}'.format(Recursion_Sum(100)))
def sub_sum(L):
oddSum = 0
evenSum = 0
index = 1
for num in L:
if index % 2:
oddSum = oddSum + num
else:
evenSum = evenSum + num
index = index + 1
return oddSum, evenSum

L1 = [1,2,3,4,5,6]
print(sub_sum(L1))
a如果有值必定输出a 如果为空必定输出第二个条件

最新回答 / qq_慕粉5466280
在电脑开始里面找到IDLE拉出桌面就可以
chinese = '这是一句中英文混合的Python字符串'
english = 'Hello World!'
print (chinese + ':' + english)
浮点型、字符串、整型、二进制
print(r''' "To be, or not to be": that is the question.
Whether it's nobler in the mind to suffer.''')
length = 3.14
wide = 1.57
area = length * wide
result = round(area,2)
print(result)
L = [75, 92, 59, 68, 99]
sum = 0
for c in L:
sum = c+sum
print(sum/len(L))
s = 'AABCDEFGHHIJ'
b = []
for a in s[0:-2]:
if a not in b:
b.append(a)
s1 = ''.join(b)
print(s1)
a = 0
L = ['Alice', 66, 'Bob', True, 'False', 100]
while a < len(L):
print(L[a])
a=a+2
def sub_sum(L):
n=0
s1=0
s2=0
for n in L:
if n%2==0:
s1=s1+n
else:
s2=s2+n
return s1, s2

L = (1, 2, 3, 4, 5, 6)
s1, s2 = sub_sum(L)
print(s1)
print(s2)
L1 = list()
L2 = list()
n = 0
while n<=99:
n = n+1
L1.append(n)
a = n*n
L2.append(a)

print(L1)
print(L2)

S1 = sum(L1)
print(S1)

S2 = sum(L2)
print(S2)
课程须知
如果您了解程序设计的基本概念,会简单使用命令行,了解中学数学函数的概念,那么对课程学习会有很大的帮助,让您学起来得心应手,快速进入Python世界。
老师告诉你能学到什么?
通过本课程的学习,您将学会搭建基本的Python开发环境,以函数为基础编写完整的Python代码,熟练掌握Python的基本数据类型以及list和dict的操作,灵活使用流程控制语句。

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