Names = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
names = []
for i in Names:
name=i.lower()
names.append(name)
for l in names:
if i not in names:
names.append(i)
print(names)
names = []
for i in Names:
name=i.lower()
names.append(name)
for l in names:
if i not in names:
names.append(i)
print(names)
2021-12-03
d = {'Alice': [50, 61, 66], 'Bob': [80, 61, 66], 'Candy': [88, 75, 90]}
num=0
for key in d.keys():
num+=1
print(num)
num=0
for key in d.keys():
num+=1
print(num)
2021-12-02
最新回答 / 慕少1566150
num=1sum=0k=1while True: if num>1000: break; num=2*k-1 sum=sum+num k=k+1print(sum)这样也可以的哟
2021-12-01
建议isdisjoint这段描述可以说是 判断两个集合是否没有交集，和函数的实际含义保持一致，读者可能会混淆 哈哈 比如我
2021-11-28
template='dong dong qiang age={}'
age='19'
result=template.format(age)
if age>=18:
print('adult',result)
age='19'
result=template.format(age)
if age>=18:
print('adult',result)
2021-11-27
print(r''' '\"TO be,or not to be \":that is the question.\n When ther it\'s nobler in the mind to suffer.' ''')
2021-11-20
num1=3.14
num2=1.57
a=num1*num2
print(round(a)) #==>4.93
num2=1.57
a=num1*num2
print(round(a)) #==>4.93
2021-11-18
