d={'Alice':89,'Bob':72,'Candy':88,'David':79,'Ellena':99}#以名字和分数建立一个dict
L=sorted(d.items(),key=lambda x:x[1])#将这个dict按照value值的大小排序输出元素以(名字,分数)为tuple的列表
print(L)
此方法适用于若需要排序的对象很多的情况,例如需要排序的list有100个元素 。
L=sorted(d.items(),key=lambda x:x[1])#将这个dict按照value值的大小排序输出元素以(名字,分数)为tuple的列表
print(L)
此方法适用于若需要排序的对象很多的情况,例如需要排序的list有100个元素 。
2020-09-05
L = [95.5, 85, 59, 66, 72]
L=sorted(L)
print(L[-1])
print(L[-2])
print(L[-3])
L=sorted(L)
print(L[-1])
print(L[-2])
print(L[-3])
2020-09-05
#举一反三
l=[]
for i in range(10):
l.append(i)
print(l)
t=tuple(l)
print(t)
l=[]
for i in range(10):
l.append(i)
print(l)
t=tuple(l)
print(t)
2020-09-04
# Enter a code
L = ['Alice', 66, 'Bob', True, 'False', 100]
num = 0
for x in L:
num = num + 1
if num % 2 == 0:
print(x)
这样做也行
L = ['Alice', 66, 'Bob', True, 'False', 100]
num = 0
for x in L:
num = num + 1
if num % 2 == 0:
print(x)
这样做也行
2020-09-04
L = ['Alice', 66, 'Bob', True, 'False', 100]
i=0
for item in L:
i+=1
if i%2==0:
print(item)
#or
print(L[1::2])
i=0
for item in L:
i+=1
if i%2==0:
print(item)
#or
print(L[1::2])
2020-09-04
#有点懒嘿嘿
L = [75, 92, 59, 68, 99]
sum=0
for ch in L:
sum+=ch
print(sum/(len(L)))
L = [75, 92, 59, 68, 99]
sum=0
for ch in L:
sum+=ch
print(sum/(len(L)))
2020-09-04
L = [75, 92, 59, 68, 99]
i = 0
sum = 0
for x in L:
sum = x + sum
i = i + 1
ave = sum/i
print(ave)
这样更方便些
i = 0
sum = 0
for x in L:
sum = x + sum
i = i + 1
ave = sum/i
print(ave)
这样更方便些
2020-09-01
s1 = 'ABC'
s2 = '123'
s3 = 'xyz'
s = s1 + s2 + s3
for ch1 in s:
for ch2 in s:
for ch3 in s:
if ch1 != ch2 and ch1 != ch3 and ch2 != ch3:
print(ch1 + ch2 + ch3)
s2 = '123'
s3 = 'xyz'
s = s1 + s2 + s3
for ch1 in s:
for ch2 in s:
for ch3 in s:
if ch1 != ch2 and ch1 != ch3 and ch2 != ch3:
print(ch1 + ch2 + ch3)
2020-08-25
r'...'表示法不能表示多行字符串,也不能表示包含'和 "的字符串,可以用r'''...'''表示
2020-08-24