哇 ,写代码的都是小机灵鬼,我硬是逐句看结果才明白为什么条件是能被3整除,能被整除的通通跳过,不能的进入正常计算,当循环到最大值的时候打印结果 6
2023-07-10
哇咔咔 ,查了半天 ,发现题都没看对,结果答案是对的 逻辑是这样的 求sum,第一步肯定是 sum=,看错题后: sum=i-100; i++;结果错的一踏糊涂,写了个棒槌 鼓励一下自己 就是玩
2023-07-08
#include <stdio.h>
int main(void)
{
int num = 1;
while (num < 21)
{
printf("%4d %6d\n", num, num *num);
num = num + 1;
}
return 0;
}
int main(void)
{
int num = 1;
while (num < 21)
{
printf("%4d %6d\n", num, num *num);
num = num + 1;
}
return 0;
}
2023-06-30
#include <stdio.h>
int main()
{
int x,y;
x = 10;
y = -3;
printf("x+y=%d\n", x+y );
printf("x-y=%d\n", x-y );
printf("x*y=%d\n", x*y );
printf("x/y=%d\n", x/y );
printf("x%%y=%d\n", x%y );
return 0;
}
int main()
{
int x,y;
x = 10;
y = -3;
printf("x+y=%d\n", x+y );
printf("x-y=%d\n", x-y );
printf("x*y=%d\n", x*y );
printf("x/y=%d\n", x/y );
printf("x%%y=%d\n", x%y );
return 0;
}
#include <stdio.h>
int main()
{
int arrFirst[3] = {4,5,6};
int arrSecond[] = {7,2,9};
int arrThird[3];
arrThird[0]=10;
arrThird[1]=0;
arrThird[2]=12;
printf("%d\n", arrFirst[1]);
printf("%d\n",arrSecond[1]);
printf("%d\n", arrThird[1]);
return 0;
}
输出结果:520
int main()
{
int arrFirst[3] = {4,5,6};
int arrSecond[] = {7,2,9};
int arrThird[3];
arrThird[0]=10;
arrThird[1]=0;
arrThird[2]=12;
printf("%d\n", arrFirst[1]);
printf("%d\n",arrSecond[1]);
printf("%d\n", arrThird[1]);
return 0;
}
输出结果:520