lambdaQuery() .between 报错如下
List<User> userList= iUserService.lambdaQuery()
.notBetween("age",25,30)
.isNotNull("email");Required type:
SFunction
<com.example.demo.parking.entity.User,
?>
Provided:
String
List<User> userList= iUserService.lambdaQuery()
.notBetween("age",25,30)
.isNotNull("email");Required type:
SFunction
<com.example.demo.parking.entity.User,
?>
Provided:
String
2021-07-08
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