变量与常量的批处理文件比较失败我想写一段简单的代码，得到一些很好的格式“时间戳”。让时间进入我的两个变量Start和End效果很好。我也可以把它打印成0：0：0。如果它小于10，我想要一个前导零，但是很明显，我收到了一个错误，它说‘没有找到参数10，或者输入错了’。我发现这似乎是要比较的变量，但我没能解决这个问题。有什么想法吗？@ECHO OFF
REM Time Calculation
FOR /F "skip=1 tokens=1-6" %%A IN ('WMIC Path Win32_LocalTime Get Day^,Hour^,Minute^,Second /Format:table ^| findstr /r "."') DO (
set Day=%%A
set Hour=%%B
set Minute=%%C
set Second=%%D
)
set /a Start=%Day%*8640000+%Hour%*360000+%Minute%*6000+%Second%*100
@ECHO ON
ping 8.8.8.8 -n 11
@ECHO OFF
FOR /F "skip=1 tokens=1-6" %%A IN ('WMIC Path Win32_LocalTime Get Day^,Hour^,Minute^,Second /Format:table ^| findstr /r "."') DO (
set Day=%%A
set Hour=%%B
set Minute=%%C
set Second=%%D
)
set /a End=%Day%*8640000+%Hour%*360000+%Minute%*6000+%Second%*100
set /a Diff=%End%-%Start%
set /a Diff=(%Diff%)/100
set /a DiffSec=%Diff%%%60
set /a Diff=(%Diff%-%Diff%%%60)/60
set /a DiffMin=%Diff%%%60
set /a Diff=(%Diff%-%Diff%%%60)/60
set /a DiffHrs=%Diff%
ECHO Laufzeit Auftraege loeschen: %DiffHrs%:%DiffMin%:%DiffSec%
:: format with leading zeroes
if %DiffSec% LSS 10 (ECHO "LESS 10")else %DiffSec% LSS 1 (ECHO "LESS 1")
::if %DiffSec% LSS 10 (set DiffSec=0%DiffSec%)else [%DiffSec%] LSS 1 (set DiffSec=00)
::if %DiffMin% LSS 10 (set DiffMin=0%DiffMin%)else [%DiffMin%] LSS 1 (set DiffMin=00)
::if %DiffHrs% LSS 10 (set DiffHrs=0%DiffHrs%)else [%DiffHrs%] LSS 1 (set DiffHrs=00)
ECHO Laufzeit Auftraege loeschen: %DiffHrs%:%DiffMin%:%DiffSec%
- 3 回答
- 0 关注
- 625 浏览
添加回答
举报
0/150
提交
取消