在对象数组中，过滤相等的对象。（所有属性都匹配）

Question

const timings = [  {startH: 10, startM: 20, endH: 11, endM: 30},  {startH: 10, startM: 20, endH: 11, endM: 30},  {startH: 9, startM: 10, endH: 11, endM: 30},  {startH: 10, startM: 20, endH: 10, endM: 30},  {startH: 10, startM: 20, endH: 11, endM: 30},  {startH: 10, startM: 20, endH: 11, endM: 30}];返回数组内所有相等的对象

Answer 1

尝试使用下一个代码：

const timings = [

  {startH: 10, startM: 20, endH: 11, endM: 30},

  {startH: 10, startM: 20, endH: 11, endM: 30},

  {startH: 9, startM: 10, endH: 11, endM: 30},

  {startH: 10, startM: 20, endH: 10, endM: 30},

  {startH: 10, startM: 20, endH: 11, endM: 30},

  {startH: 10, startM: 20, endH: 11, endM: 30}

];

Array.prototype.uniqueObjects = function (props) {

    function compare(a, b) {

      var prop;

        if (props) {

            for (var j = 0; j < props.length; j++) {

              prop = props[j];

                if (a[prop] != b[prop]) {

                    return false;

                }

            }

        } else {

            for (prop in a) {

                if (a[prop] != b[prop]) {

                    return false;

                }

            }

        }

        return true;

    }

    return this.filter(function (item, index, list) {

        for (var i = 0; i < index; i++) {

            if (compare(item, list[i])) {

                return false;

            }

        }

        return true;

    });

};

 

var uniqueObject = timings.uniqueObjects(["startH", "startM", "endH", "endM"]);

console.log(uniqueObject);