这样做的目的是让用户每行输入一个数字，当用户不再希望继续时，他们应该能够输入一个空行，当发生这种情况时，程序应该给您一条包含最大数字的消息。问题是我无法用空行中断循环。我不知道该怎么做。我检查了其他问题以寻求解决方案，但找不到任何有帮助的内容。我也无法分配scan.hasNextInt() == null....我确信有一个我没有想到的快速且合乎逻辑的解决方案。import java.util.*;public class Main { public static void main(String[] args) { Scanner scan = new Scanner(System.in); System.out.println("Enter a number and press [Enter] per line, when you no longer wish to continue press [Enter] with no input.(empty line)"); int x = 0; while(scan.hasNextInt()){ int n = scan.nextInt(); if (n > x){ x = n; } } System.out.println("Largets number entered: " + x); }}
2 回答
阿波罗的战车
TA贡献1862条经验 获得超6个赞
这应该可以解决您的问题：
import java.util.Scanner;
public class StackOverflow {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter a number and press [Enter] per line, when you no longer wish to continue press [Enter] with no input.(empty line)");
int x = 0;
try {
while(!scan.nextLine().isEmpty()){
int num = Integer.parseInt(scan.nextLine());
if(num > x) {
x = num;
}
}
} catch (NumberFormatException e) {
e.printStackTrace();
}
System.out.println("Largest number entered: " + x);
scan.close();
}
}
一只甜甜圈
TA贡献1836条经验 获得超5个赞
import java.util.*;
public class main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("Enter a number and press [Enter] per line, when you no longer wish to continue press [Enter] with no input.");
String str = scanner.nextLine();
int x = 0;
try {
while(!str.isEmpty()){
int number = Integer.parseInt(str);
if (number > x){
x = number;
}
str = scanner.nextLine();
}
}
catch (NumberFormatException e) {
System.out.println("There was an exception. You entered a data type other than Integer");
}
System.out.println("Largets number entered: " + x);
}
}
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