# Enter a code
# coding:utf-8
d = {
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49,
'Gaven': 86
}
keys = d.keys()
for key in keys:
print('名字：{}；\t成绩：{}'.format(key, d.get(key)))
# coding:utf-8
d = {
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49,
'Gaven': 86
}
keys = d.keys()
for key in keys:
print('名字：{}；\t成绩：{}'.format(key, d.get(key)))
2021-03-12
L = [75, 92, 59, 68, 99]
sum = 0.0
for x in L:
sum+=x
sum = sum/len(L)
print(sum)
sum = 0.0
for x in L:
sum+=x
sum = sum/len(L)
print(sum)
2021-03-11
L = ['Alice', 66, 'Bob', True, 'False', 100]
num = 1
for i in L:
if num % 2 ==0:
print(i)
num += 1
else:
num += 1
continue
num = 1
for i in L:
if num % 2 ==0:
print(i)
num += 1
else:
num += 1
continue
2021-03-11
s1 = 'ABC'
s2 = "123"
s3 = 'xyz'
for ch1 in s1:
for ch2 in s2:
for ch3 in s3:
print(ch1+ch2+ch3)
s2 = "123"
s3 = 'xyz'
for ch1 in s1:
for ch2 in s2:
for ch3 in s3:
print(ch1+ch2+ch3)
2021-03-11
number = 0
sum = 0
while number <=1000:
if number % 2 != 0:
number += 1
continue
else:
sum += number
print(number,sum)
number += 1
sum = 0
while number <=1000:
if number % 2 != 0:
number += 1
continue
else:
sum += number
print(number,sum)
number += 1
2021-03-11
s1='ABC'
s2='123'
s3='xyz'
for x in s1+s2+s3:
for y in s1+s2+s3:
for z in s1+s2+s3:
if (x==y or x==z or y==z):
continue
print(x+y+z,end='\t')
s2='123'
s3='xyz'
for x in s1+s2+s3:
for y in s1+s2+s3:
for z in s1+s2+s3:
if (x==y or x==z or y==z):
continue
print(x+y+z,end='\t')
2021-03-10
最赞回答 / qq_慕移动8044885
在python编译器中进行这段代码的时候，在while循环的下面，左边的提示符为“...”表示下面内容都在该循环下。这时候只要在输入最后输出语句那行前敲一下回车就可以结束循环体的编写了
2021-03-10
最新回答 / 自学Python
<...图片...>截图你会看的清楚点：第一行你这样写打印出的每个单词后面都会有逗号；S后面跟个逗号就可以第一行的 里面 l, i, s ... ,其实就是变量 只不过没有值，你在第而部分有给他赋值了，应该重新申请变量结合我发的图片第三部分，a. format 写错 你写成 formate b.你用‘ 引号 ，也是不对的 具体的可以看我给你的截图希望对你有帮助
2021-03-10
最赞回答 / 慕侠0184542
for cube in L:意思是把字符串L中的每一个元素依次赋值给cubecube分别等于
[1,2,3], [5, 3, 2], [7,3,2]cube[0]即代表第一个数字
2021-03-08